Master Electrician Practice Exam

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Enhance your knowledge for the Master Electrician Test with multiple choice questions and detailed explanations. Prepare efficiently with our quiz and boost your confidence for the exam day!

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What is the maximum load in VA that the branch-circuit conductors of a 20-ampere, 277-volt circuit are permitted to carry for continuous lighting?

4000 VA
4432 VA
5000 VA
5500 VA

The correct answer is: 4432 VA

The maximum load that branch-circuit conductors can carry for continuous lighting in a 20-ampere, 277-volt circuit is calculated based on the National Electrical Code (NEC) guidelines, which state that continuous loads should not exceed 80% of the circuit's maximum capacity. To find the allowable load for a 20-ampere circuit, you first calculate the total capacity by multiplying the current (20 A) by the voltage (277 V): \[ 20 \text{ A} \times 277 \text{ V} = 5540 \text{ VA} \] Since the lighting load is considered a continuous load, you apply the 80% rule: \[ 5540 \text{ VA} \times 0.80 = 4432 \text{ VA} \] Thus, the maximum load that the branch-circuit conductors can safely carry for continuous lighting is 4432 VA. This figure ensures that the circuit operates efficiently and reduces the risk of overheating or electrical failure over time. The other options do not adhere to the 80% rule, making them unsuitable for continuous loading scenarios.